Question

6. A field is in the shape of a quadrilateral. One of its diagonals is 28m and the perpendicular
distances of the other two vertices to the diagonal are 32.5m and 22m. Find the area of the field.
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Answer 1

Answer:

area of first triangle in quadrilateral is 1/2 × base× height

so 1/2 × 28 × 32.5= 455m

area of second triangle of quadrilateral is 1/2× 28×22= 308m

area of quadrilateral is 455+308= 763m