Question

6. (a) Find the smallest number which when divided by 45 and 60 leaves 7 as the
remainder in each case. ​

Answer 1

ANSWER : 19 is the answer

Answer 2

Answer:

2014

Step-by-step explanation:

1. here, the smallest number indicates that we need to find the LCM (Least Common Multiple)
2. the reminder needs to be 7, so, to cancel it out, we subtract 7 from each of the numbers. (45-7 = 38 and 60-7 = 53)

now, lets solve it.

• we basically need to find the LCM of 38 and 53.
• the process is in the attachment below.

this shows that the LCM of the two numbers is 2 x 19 x 53 = 2014.

so, the smallest number which divides 45 and 60 equally by leaving a remainder of 7 is 2014.

please mark as brainliest.

thanks!