6. (a) Find the smallest number which when diviu remainder in each case. (b) Find the smallest number which when divided by 40, 60 and 100 leaves 24 as the leaves 10 as the
Answers
Answered by
1
Answer:
Here 25=5×5=5^2
40=2×2×2×5=2^3×5
60=2×2×3×5=2^2×3×5
Therefore LCM of 25,40,60 is
=2^3×3×5^2
=8×3×25
=600
Since remainder is 7
The required number is =600+7
=607
Similar questions