Question

6.
A force of 200 N is required to push a car of mass 500 kg, slowly at constant speed on a
level road. If a force of 500 N is applied, the acceleration of the car (in ms will be
(A) zero
(B) 0.2
(C) 0.6
(D) 1.0
please tell with explanation ​

Answer 1

Answer:

(C) 0.6 m/s

Explanation:

When 200 N force is applied on the car, it moves with constant velocity.

Hence, the force of friction from the road is 200 N

Mass of car = 500 kg

Now, the force applied (F) = 500 N

Let the acceleration be a.

According to the Newton's second law of motion,

F(net) = mass × acceleration = ma

Here, F(net) = Force applied - Friction

Force applied - Friction = ma

500 - 200 = 500 × a

=> 300 = 500 × a

=> a = 300/500 = 0.6 m/s

Hence, the required acceleration = 0.6 m/s.