Question

6. A force of 50 N acts on a body and moves it a distance of 4 m on a horizontal surface.
Calculate the work done if the direction of force is at an angle of 60° to the horizontal
surface. What will be the value of work done if angle is 30° instead of 60°?​

Answer 1

Explanation:

work = F × displacement × cos theta

when angle is 60

work = 50 ×4 cos 60

= 50 × 4/2

=50×2 =100 J

when angle is 30

work = 50 ×4×cos30°

50× root3/2 ×4

=100root3 J

Answer 2

Answer:

w=f×s×cos¶

w=50×4×cos60

w=200×1/2

w=100j

in case the angle was 30°

w=f×s×cos¶

w=50×4×cos30

w=200×√3/2

w=100×√3

W=100√3

hope you got the answer !!!