6. A garrison of 200 men had provisions for 45 days. After 15 days, 40 more men join the
garrison. Find the number of days for which the remaining food will last.
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Answers
Answer:
Hi ,
This is related to Inverse Proportion.
If two quantities are so related that
an increase in one causes a
corresponding decrease in the other
( or vice versa ) then they are said
to be in Inverse variation.
If two quantities x and y are in
Inverse variation then
x × y = k ( constant )
200 men had provisions for 45 days.
After 15 days ,
200 men had provisions for 30days.
Now ,
i ) Number of men ( x1 ) = 200
Provisions finished ( y1 ) = 30 days
ii ) after 15 days number of men
joined are 40.
Therefore,
Number of men
after 15 days ( x2 ) = 240
Let food last in Number of days = y2
x2 × y2 = x1 × y1
y2 = ( x1 × y1 ) / x2
y2 = ( 200 × 30 ) / 240
= 25
Therefore,
Remaining food will last in 25days.
I hope this helps you.
:)
Step-by-step explanation:
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Answer:
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Step-by-step explanation:
Hi ,
This is related to Inverse Proportion.
If two quantities are so related that
an increase in one causes a
corresponding decrease in the other
( or vice versa ) then they are said
to be in Inverse variation.
If two quantities x and y are in
Inverse variation then
x × y = k ( constant )
200 men had provisions for 45 days.
After 15 days ,
200 men had provisions for 30days.
Now ,
i ) Number of men ( x1 ) = 200
Provisions finished ( y1 ) = 30 days
ii ) after 15 days number of men
joined are 40.
Therefore,
Number of men
after 15 days ( x2 ) = 240
Let food last in Number of days = y2
x2 × y2 = x1 × y1
y2 = ( x1 × y1 ) / x2
y2 = ( 200 × 30 ) / 240
= 25
Therefore,
Remaining food will last in 25days.
I hope this helps you.
:)