Chemistry, asked by Anonymous, 4 months ago

6
A gas mixture consisting of He and CH, gases in
mole ratio 4:1 is present in a vessel at a pressure of
20 bar. Due to a fine hole in the vessel, the gas
mixture undergoes effusion. What is the composition
(or ratio) of the initial gas mixture that is effused out?​

Answers

Answered by sahumanoj0331
1

Answer:

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Question From class 11 Chapter STATES OF MATTER : GASES AND LIQUIDS

A gas mixture consisting of He and

gases in mole ratio 4:1 is present in a vessel at a pressure of 20 bar. Due to a fine hole in the vessel, the gas mixture undergoes effusion. What is the composition (or ratio) of the initial gas mixture that is effused out?

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Text Solution

Solution :

If the total number of moles in the mixture be n, then number of moles of He and

are

or , 0.8 n and 0.2 n respectively. <br> In the mixture, the partial pressure of

<br>

bar and that of

<br>

bar <br> Rate of effusion of a gas at constant temperature

, <br> where P=pressure of the gas and M=molar mass of the gas. <br> Therefore, the rate of effusion of He gas,

<br> or,

and that of

gas,

<br>

<br>

The rato of number of moles of He and

(composition) in the initial gas mixture effused out is 8:1.

Answered by dubeyruchi7575
0

Answer:

hii bro gm.............kya kar rhe ho

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