6. A hammer of mass 400 g, moving at 30 m s-1, strikes a nail. The nail stops the
hammer in a very short time of 0.01 s. What is the force of the nail on the hammer?
Answers
Answered by
3
Answer:
Given,
Mass, m=0.4kg
Change in velocity = initial velocity – final velocity
ΔV=30−0=30ms
−1
Force, F=
t
mΔV
=
0.01
0.4×30
=1200N
Hence , force is 1200 N
Answered by
1
Answer:
Given,
Mass, m=0.4kg
Change in velocity = initial velocity – final velocity
ΔV=30−0=30ms −1
Force, F= t
mΔV
= 0.01
0.4×30
=1200N
Hence , force is 1200 N
Explanation:
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