Question

6. A long solenoid of 10 turns / cm has a small loop of area I cm2 inside with normal of loop is parallel to axis of solenoid. Calculate voltage in loop if current is changed in solenoid from 1A to 2A in 0.1 sec​

Answer 1

Answer:

Here, lN=10 turns per cm= 1000 turns per m

A=ccm2=3×10−4m2ordtdI=0.24−2=10As−1

Also, 

ϵ=dtdϕ=dtd(BA)=adtd(μolNI)=aμ0(lN)dtdi

3×10−4×4π×10−7×1000×10=3.8×10−6V

Hope this helps you

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