6. A man goes 15 m due west and then 8 m due north How far is he from the starting point?
(A) 15 m
(B) 8 m
(C) 17 m
(D) 16 m
Answers
Answered by
1
Answer:
First the person moves from A to B and then B to C.
His distance from the starting point is AC.
AC can be calculated using Pythagoras Theorem.
Applying Pythagoras theorem
(AB)
2
+(BC)
2
=(CA)
2
(15)
2
+(8)
2
=(x)
2
225+64=(x)
2
x
2
=289
x=
289
=17m
Hence the man is 17m from the starting point.
Answered By
toppr
Answered by
0
( C ) 17 m
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