Question

6. A man holds a spherical
shaving mirror of radius of
curvature 60cm, and focal
length 30 cm, at a distance of
15 cm, from his nose. Find the
position of image, and calculate
the magnification
​

Answer 1

Given:-

• Radius of curvature ,R = 30cm

• Focal length , f = -30cm

• Object- distance = -15cm

To Find:-

• Image distance & Magnification

Solution:-

The shaving mirror is concave mirror.

By using mirror formula

• 1/v +1/u = 1/f

Substitute the value we get

→ 1/v = 1/f - 1/u

→ 1/v = 1/-30 - 1/(-15)

→ 1/v = -1/30 +1/15

→ 1/v = -1+2/30

→ 1/v = 1/30

→ v = + 30cm

∴ The image- distance is 30cm

Positive sign show the image formed is Virtual.

Now , Calculating the Magnification

• m = -v/u

Substitute the value we get

→ m = -30/-15

→ m = 2cm

∴ The magnification of the mirror is 2cm

Answer 2

Answer:

6. A man holds a spherical

shaving mirror of radius of

curvature 60cm, and focal

length 30 cm, at a distance of

15 cm, from his nose. Find the

position of image, and calculate

the magnification