Question

6.
A man runs at a speed of 4 ms to overtake a standing bus. When he is 6 m behind the door at
t=0, the bus starts to move forward and continues with a constant acceleration of 1.2 ms. If the man
reaches the door in time t, then the time can be obtained by the equation
a) 4t=6+0.61 b) 1.21= 41
C) 46 = 1.20
d) 6+41 = 0.61
​

Answer 1

Answer:

Option (a) i.e, 4t=6+0.61 is the answer.

Hope this helps you ;)

If yes, then please mark this as the brainliest answer!