Question

6. A man spends 1/3 of his salary on rent and 2/5 of the remainder on food. He saves the rest of his
Income. If his savings amount to sh 4,200, find his income.
(3 mksy​

Answer 1

Given :-

• A man spends (1/3) of His salary on Rent.
• (2/5)th of Rest on Food.
• Saves Rest which is Rs.4200 .

To Find :-

• His Total income ?

Solution :-

Let His Total income is Rs.x .

→ Spend on Rent = (1/3) of Total income = (x/3)..

→ Left income = x - (x/3) = (2x/3)

Now,

→ Spend on Food = (2/5)th of Rest = (2/5) of (2x/3) = (2/5) * (2x/3) = (4x/15).

So,

→ Left income After Spending on Food = (2x/3) - (4x/15) = (10x - 4x) /15 = (6x/15) = (2x/5) .

Now, given That, he saves Rest and that is Rs.,4200.

Therefore,

→ (2x/5) = 4200

→ 2x = 4200 * 5

→ x = 2100 * 5

→ x = Rs.10,500 (Ans.)

Hence, His Total income is Rs.10,500.

Answer 2

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$\huge\tt{GIVEN:}$

• a man spends 1/3 of his salary on rent
• 2/5 of the rest on food
• He saved 4200

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$\huge\tt{TO~FIND:}$

• His income

_______________________

$\huge\tt{SOLUTION:}$

Let his income be x

↪ Money spent of rent = (x/3)

↪Left balance = x -(x/3) = (2x/3)

_______________________

Then,

↪Money spent on the food = (2/5) of (2x/3)

=> (2/5)×(2x/3)

=> (4x/15)

_______________________

As in this case, we know that he saves ₹ 4,200

Henceforth,

➡(2x/5) = 4,200

➡2x = 2,100

➡x = ₹10,500

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