Question

6.
A man standing between two parallel walls fires a gun. He hears an echo after 1.5 seconds and another
one after 2.5 seconds and yet another one after 4 seconds. Determine the separation of the walls. (Take velocity
of sound 340 m/s)​

Answer 1

Answer:

Suppose d is the total distance between two cliffs and x is the distance between the man and one cliff.

2x=v×t

1

x=

2

v×t

1

=

2

340×1.5

=255 m

2(d−x)=v×t

2

(d−x)=

2

v×t

2

(d−x)=

2

v×t

2

(d−x)=

2

340×3.5

(d−x)=595 m

d=595+x

=595+255

=850 m