Question

6. A man stands in front of a cliff and fires a gun and hears
The echo after 2.5s. He moves a distance x from the cliff
and fires the gun again. He hears the echo after 3s. If the
velocity of sound is 330m s!, find the distance x.

Answer 1

Answer:

Let the distance of the cliff from the initial position of the man be d m.

So, the distance traveled by sound in 3 sec=2d m

So, speed of sound, S=TimeDistance

S=32d.....(i)

On moving closer to the cliff by a distance of 82.5 m, the distance=2(d−82.5) m

So,

S=td

S=2.52(d−82.5)

=2.52d−2×82.5.....(ii)

Therefore form equation (i) and (ii)

32d=2.52d−2×82.5

5d=6d−495

d=495 m

Explanation:

hope its helpful to you