Question

6. A man travels 90 km due East and then 56 km due South. How far is he from the starting point?
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Answer 1

A is the starting point 15

A to B = 90km

B to C = 56km

AC²= AB² +BC²

AC = (90)²+ C56)² = 11236

= √11236

= √106x106

AC=106 km