Question

6.A man walking north after travelling 15 m then takes right turn and walk 16 m, what is the displacement from original position?
The man who will answer correct will be marked as brainliest​

Answer 1

Answer - 10m(east)

hope it helps

Answer 2

The Displacement Of The Man Is 21.9m In The North-east Direction.

GIVEN

Distance traveled in north = 15 m

Distance traveled on Right of north = 16 m

TO FIND

Displacement of the man

SOLUTION

We can simply solve the above problem as follows-

We know that displacement is the shortest distance between the final and initial points.

Displacement is a vector quantity, it has both magnitude and direction.

It is given,

Let the initial position of the man be, OO

Distance Travelled in the North, OA = 15m

Distance traveled in the East, OB = 16 m

So, the final position of the man is 'B'

Displacement =shortest Distance between the final and initial position of the man

Displacement = OB

We know that OAB is a right-angle triangle.

We can calculate the length of OB by applying the Pythagoras theorem in ∆OAB

So,

${OB}^{2} = {OA}^{2} + {AB}^{2}$

${OB}^{2} = {15}^{2} + {16}^{2}$

${OB}^{2} = 225 + 256$

${OB}^{2} = \sqrt{481}$

OB = 21.9m

Therefore OB = 21.9 m

∠BOA = 45°

Hence, the displacement of the man is 21.9m in the North-East direction.

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