Question

6. A man walks for 5 minutes with a velocity of 1m/s then the displacement covered by the man is 1) 50m 2) 300m 3) 100m 4) 30m​

Answer 1

Answer

Time during motion in west is t

1

=

2m/s

30m

=15s

Time during motion in north is t

2

=

4m/s

40m

=10s

net distance is 30m+40m=70m

so average speed will be v=

(15+10)s

70m

=2.8m/s

Displacement is a vector quantity so the net displacement will be the vector sum.

North and West are perpendicular to each other so the net displacement will be x=

30

2

+40

2

=50m

so magnitude of the average velocity will be V=

25s

50m

=2m/s

Answer 2

Answer:

2) 300m

Explanation:

here is your answer and mark it as brainliest .