Question

6. A manufacturer knows that the condensors ho makes contain on the average 1% dofectives. He packs them in boxes
of 100. What is the probability that a box picked at random will contain 3 or more faulty condensers ?
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Answer 1

Answer:

Since the manufacturer knows that 1% of their items is defective.

So out of 100 items,the probability of selecting defective items is 0.01.

Here, n=100,p=0.01 and Mean(m)=np=1;

Since,the value of n is very high and p is very low So using the formula of Poisson distribution, we have:

P(X>=3) = 1-[P(X=0)+P(X=1)+P(X=2)]

Where,P(X=r)=((m^r)*e^(-m))/(r!)

Therefore,

P(X>=3)=1–(e^-1+e^-1+(e^-1/2))

P(X>=3)=0.08037

Step-by-step explanation:

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