Question

6. A motorbike running at 60km/he in 2.5seconds calculate 1) retardation
ii) Distance covered


​

Answer 1

Answer:

Initial velocity of truck ,

u = 90 km/h = 90 * 5/18=25 m/s

Final velocity v=0

S= 25 m

Using third equation of motion ,

v^2 - u^2 = 2 a s

0 - 625 = 2 a *25

-625 = 2 a * 25

a = -625/2 * 25= - 12.5 m / sec square

Answer 2

Answer:

2 is answer eyodigdhkxhkxukdykdhkdkydkhxkysi6sykxykdiydkydkydiydkyxukdkyzkhxkydkyxkjxukxmj