Question

6 . A number consists of two digits of which tens digit exceeds the unit digit

by 7 . The number itself is equal to 10 times the sum of its digits . Find the

number .​

Answer 1

Answer:

Hello,

let uniti digit be x,

tens  digit = x+7

then value no:

10(x+7)+x;

10x+70+x;

11x+70;

ten times sum of digits

10(x+x+7);

10(2x+7);

20x+70;

according to question 

20x+70=11x+70;

20x-11x=70-70;

9x=0,

x=0

therefore unit digit = 0

tens digit=0+7

therefore no. =70

bye :-)

Step-by-step explanation:

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Answer 2

Answer:

Hello,

let uniti digit be x,

tens  digit = x+7

then value no:

10(x+7)+x;

10x+70+x;

11x+70;

ten times sum of digits

10(x+x+7);

10(2x+7);

20x+70;

according to question 

20x+70=11x+70;

20x-11x=70-70;

9x=0,

x=0

therefore unit digit = 0

tens digit=0+7

therefore no. =70

Step-by-step explanation:

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