Question

6. A particle is moving along straight line with initial velocity 48 m/sec and acceleration –10m/s2

. The

distance travelled by particle in 5th second is :

(A) 3m (B) 115 m (C) 5

17

m (D) 5

14

m

Answer 1

your solution has been provided by me

Answer 2

S=ut+(1/2)at^2
S=48*5+(0.5*-10*5*5)
S=115 m



Hope it helps:)