Question

6. A player is rolling a die. In the first three throws, he
gets a 6 each time. What is the probability that he will
get a 6 in the fourth throw?​answr fast

Answer 1

Answer:

The prob of getting 6 is $\frac{1}{6}$

If he wants to get it 4 times, then:

$\frac{1}{6} * \frac{1}{6} * \frac{1}{6} * \frac{1}{6} = \frac{1}{1296}$