Question

6.
A powerful motorcycle can accelerate from rest to 32 m/s in only 4s.
(a) What is its average acceleration?
(b) How far does it travel in that time?

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Answer 1

Answer: Average acceleration= 8m/s²

Distance travelled in that time= 64m

Explanation:

We know,

(a) average acceleration=

(Final velocity - initial velocity) / time

=(32-0) / 4

=8m/s²

(b) distance travelled in that time=

=1/2× acceleration× (time)²

=0.5× 8× 4²

= 64m

Answer 2

Answer:

Explanation:

Given,

Initial velocity, u = 0 m/s

Final velocity, v = 32 m/s

Time taken, t = 4seconds

To Find,

a. Acceleration, a

b. Distance covered, s

Formula to be used,

1st equation of motion, v = u + at

3rd equation of motion, v² - u² = 2as

Solution,

Putting all the values, we get

v = u + at

⇒ 32 = 0 + a × 4

⇒ 32 = 4a

⇒ 32/4 = a

⇒ a = 8 m/s².

Hence, the acceleration is 8 m/s².

b. Now, distance covered,

v² - u² = 2as

⇒ (0)² - (32)² = 2 × 8 × s

⇒ 1024 = 16s

⇒ 1024/16 = s

⇒ s = 64 m

Hence, the distance covered is 64 m.