Question

6)A quadratic polynomial in x with real coefficients is of the form
ax^2 + bx + c, where a, b, c are real numbers with a = 0.
Formula of quadratic equation ax^2 + bx + c = 0 is
X = -b + √b^2-4ac/2a here b2 - 4ac 0​

Answer 1

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Answer 2

Answer:

HERE IS YOUR ANSWER MATE......;

In the aforementioned polynomial, let a2 = x.

Now, the polynomial becomes,

x^2 + 4x + 5

Comparing with ax^2 + bx + c,

Here, b^2 – 4ac = 4^2 – 4(1)(5) = 16 – 20 = -4

So, D = b2 – 4ac < 0

As the discriminant (D) is negative, the given polynomial does not have real roots or zeroes

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