Question

6. A quadratic polynomial whose one zero is 6 and sum of the zeroes is 0.is (a) x2 - 6x + 2 (b) x - 36 (c) XP-6 (d) x2-3​

Answer 1

Answer:

${x}^{2} - 36 = 0.$

Step-by-step explanation:

$\alpha = 6 \\ \\ \alpha + \beta = 0 \\ \\ 6 + \beta = 0 \\ \\ \beta = - 6 \\ \\ therefore \: \: \: \alpha \beta = 6 \times - 6 = - 36 \\ \\ {x}^{2} - ( \alpha + \beta ) + \alpha \beta = 0 \\ \\ {x}^{2} - 0x - 36 = 0 \\ \\ {x}^{2} - 36 = 0 \: \: \: ...(i)$