Question

6. A quantity of PCI, was heated in a 12 dm' vessel at 250°C.
PCI PCI + C16
At equilibrium, the vessel contains 0.21 mole PCI,,0.32 mole PCI, and 0.32
mole Cl, Compute the equilibrium constant K (Kc =0.040) Ans.​

Answer 1

PCl

5(g)

⇌PCl

3(g)

+Cl

2(g)

0.1 0.2 0.2

given, Volume of vessel =10 litres

K=

[PCl

5

]

[PCl

3

][Cl

2

]

=

(0.1/10)

(0.20/10)(0.20/10)

=0.04

equilibrium constant of this reaction is order.