Question

6. A rectangle of length 50 m and width 30 m was to be fenced along the
boundaries. Find the perimeter of another rectangle of twice the length and half
the width of the given rectangle.

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Answer 1

Answer:

twice the leangth 100 m

half of width 15 m

now

perimeter of rectangle= 2(l+b)

=2(100+15)

n. = (2×115)

= 320