Question

6) A rectangular floor having length 3.5 m and breadth 2 m is covered with square tiles of side
50cm.
(i) How many tiles will be needed to cover the entire floor?
(ii) what is the cost of flooring if the cost per tile is Rs. 60 ?

Answer 1

Answer:

solution:

area of a rectangle=lXb

$3.5 \times 2$

= 7m

= 7X100

= 700cm

tiles will be needed to cover the entire

floor =

$\frac{700}{50}$

18 tiles

cost of tiles = Rs 60

cost of total tiles = 60X18

= Rs 1060

Answer 2

Answer:

solution:

solution:area of a rectangle=lXb

solution:area of a rectangle=lXb3.5×23.5 \times 23.5×2

solution:area of a rectangle=lXb3.5×23.5 \times 23.5×2= 7m

solution:area of a rectangle=lXb3.5×23.5 \times 23.5×2= 7m= 7X100

solution:area of a rectangle=lXb3.5×23.5 \times 23.5×2= 7m= 7X100= 700cm

solution:area of a rectangle=lXb3.5×23.5 \times 23.5×2= 7m= 7X100= 700cmtiles will be needed to cover the entire

solution:area of a rectangle=lXb3.5×23.5 \times 23.5×2= 7m= 7X100= 700cmtiles will be needed to cover the entirefloor =

solution:area of a rectangle=lXb3.5×23.5 \times 23.5×2= 7m= 7X100= 700cmtiles will be needed to cover the entirefloor =70050\frac{700}{50}

solution:area of a rectangle=lXb3.5×23.5 \times 23.5×2= 7m= 7X100= 700cmtiles will be needed to cover the entirefloor =70050\frac{700}{50} 50

solution:area of a rectangle=lXb3.5×23.5 \times 23.5×2= 7m= 7X100= 700cmtiles will be needed to cover the entirefloor =70050\frac{700}{50} 50700

solution:area of a rectangle=lXb3.5×23.5 \times 23.5×2= 7m= 7X100= 700cmtiles will be needed to cover the entirefloor =70050\frac{700}{50} 50700

solution:area of a rectangle=lXb3.5×23.5 \times 23.5×2= 7m= 7X100= 700cmtiles will be needed to cover the entirefloor =70050\frac{700}{50} 50700

solution:area of a rectangle=lXb3.5×23.5 \times 23.5×2= 7m= 7X100= 700cmtiles will be needed to cover the entirefloor =70050\frac{700}{50} 50700 18 tiles

solution:area of a rectangle=lXb3.5×23.5 \times 23.5×2= 7m= 7X100= 700cmtiles will be needed to cover the entirefloor =70050\frac{700}{50} 50700 18 tilescost of tiles = Rs 60

solution:area of a rectangle=lXb3.5×23.5 \times 23.5×2= 7m= 7X100= 700cmtiles will be needed to cover the entirefloor =70050\frac{700}{50} 50700 18 tilescost of tiles = Rs 60cost of total tiles = 60X18

solution:area of a rectangle=lXb3.5×23.5 \times 23.5×2= 7m= 7X100= 700cmtiles will be needed to cover the entirefloor =70050\frac{700}{50} 50700 18 tilescost of tiles = Rs 60cost of total tiles = 60X18= Rs 1060