6. A rectangular lawn 115 m long and 64 m broad has two cross-paths at right-angles, one 2 m wide.
running parallel to its length and the other 2.5 m wide, running parallel to its breadth. Find the
cost of gravelling the paths at 114 per
m2
fo
(iv)
Answers
Answer:
Length of the rectangular field, CD = 115 cm
Breadth of the rectangular field, BC = 64 m
∴ Area of the rectangular lawn ABCD = 115 m 64 m = 7360 m2
Area of the road PQRS = 115 m 2 m = 230 m2
Area of the road KLMN = 64 m 2.5 m = 160 m2
Clearly, the area of EFGH is common to both the two roads.
∴ Area of EFGH = 2 m 2.5 m = 5 m2
∴ Area of the roads = Area (KLMN) + Area (PQRS) − Area (EFGH)
= (230 m2 + 160 m2) − 5 m2 = 385 m2
Rate of gravelling the roads = Rs 60 per m2
∴ Total cost of gravelling the roads = Rs (385 60)
= Rs 23,100
Answer:
23,100
Step-by-step explanation:
Length of the rectangular field CD=115cm.
breath of the rectangular field BC=64cm.
area of the rectangular lawn AB CD =115m64m=7360m².
area of the road PQRS=115m2m =230m².
area of the road KLMN =64m2.5m=160m².