Question

6. A rectangular lawn measuring 50 m by 36 m is surrounded externally by a path which
is 2 m wide. Find the area of the path. Also calculate the cost of levelling of the path at
16 per m2​

Answer 1

Step-by-step explanation:

length(l) of lawn = 50m

breadth(b)of lawn = 36m

width of path = 2m

so the,

length(L) of outer rectangle = 50+2+2 = 54m

breadth(B) of outer rectangle = 36+2+2 = 40m

Area of path = Area of outer rectangle - Area of inner lawn

= L×B - l×b

= 54×40 - 50×36

= 2160 - 1800

=360m^2

Cost of levelling path = 360×3.25

=Rs.1170

PLEASE MARK AS BRAINLIESTS

Answer 2

$answer$

Solution

Let the length and breadth of rectangular lawn be L and B

Formula:

Area of a rectangle = length × breadth

So,

$50m \: by \: 36m \: or \: 50m \times 36m$

$area \: of \: rectangle = 1800 {m}^{2}$

$x = 1180 {m}^{2}$

In this case :

Both length and breadth gets increased by 2 from both their ends

$= > length(l) = 50 + 2 + 2 = 54m$

$= > breadth(b) = 36 + 2 + 2 = 40m$

Formula:

$area \: of \: rectangle + path = l \times b$

$= > area \: of \: rectangle + path = 54 \times 40$

$= > z = 2160 {m}^{2}$

Area of path= (z) - (x)

$area \: of \: path = 2160(z) - 1800(x)$

$= 360 {m}^{2}$

Now the area of path is 360m2

Therefore the cost of levelling of the path

$= > area \: of \: path(360) \times 16 = rs5760$

$hence \: the \: cost \: of \: levelling \: the \: path \: is \: = \: rs 5760$

$ans \: rs5760$

_________×____________

Hope it helps you!

Thankyou❤