6. A rectangular lawn measuring 50m by 36m is surrounded externally by a path which is 2m wide. Find the
area of the path also calculate the cost of leveling of the path at Rs.20 per m2
Answers
Given:
- The length of a rectangular lawn is 50m
- The breadth of the rectangular lawn is 36m
- It is surrounded externally by a path which is 2m wide.
To find:
- The area of the path
- And the cost of levelling the path at Rs 20 per m sq.
So,
According to the question, image is attached
So,
- PQRS is the rectangle with length 50m and breadth 36m
Area of the rectangle PQRS = (l*b) unit sq.
Area of the rectangle PQRS = (50*36) m sq.
Area of the rectangle PQRS = 1800 m sq.
Now,
- ABCD is the rectangle with length (50+2+2) = 54m and breadth (36+2+2) = 40m, by adding the 2m wide path.
Area of the rectangle ABCD = (l*b) unit sq.
Area of the rectangle ABCD = (54*40) m sq.
Area of the rectangle ABCD = 2160 m sq.
So,
Area of the 2m wide path = [area of rectangle ABCD - Area of rectangle PQRS]
Area of 2m wide path = 2160 - 1800
Area of 2m wide path = 360 m sq.
Now,
The cost of levelling 1 m sq = Rs 20
Then,
Cost of levelling 360 m sq = 20*360 = Rs.7200
Hence
- The cost of levelling the 2m wide park is 7200
Answer:
Given :-
- Length = 50 m
- Breadth = 36 m
- It is surrounded by 2 m wide path
To Find :-
- Area of path at Cost of levelling at ₹20 per m²
Solution :-
As we know that
Area of Rectangle = L × B
Area of lawn = 50 × 36
Area of lawn = 1800 m²
Now,
When 2 m added to all sides
Length = (50 + 2 + 2) = 54 m
Breadth = (36 + 2 + 2) = 40 m
Now,
New Area = 54 × 40
Area = 2160 m²
Now,
Area of path = 2160 - 1800
Area of path = 360 m²
Total cost = 360 × ₹20
Total cost = ₹7200