6. A room is 10.2 m long, 8.5 m wide and
4.6 m high. It has a door measuring
1.5 m x 2.6 m and a window measuring
2 m x 1.7 m. Find the cost of tiling the
walls at the rate of 13.50 per sq. m.
Answers
Answer:
Cost of Tiling 164.74 m² = ₹ 2,223.99
= ₹ 2,224 (approximately)
Step-by-step explanation:
We know that,
The room has a dimension, 10.2 × 8.5 × 4.6
(This is not multiplication, just for reference we write it like that, and each '×' is read as 'by'.)
Door has a dimension of 1.5 × 2.6
also,
window has a dimension of 2 × 1.7
Now, we must find the area of the wall on order to paint,
Thus,
Area of Wall = Total S.A of the 4 sides - Area of Door - Area of window
We know that,
Total Surface area of the 4 sides = 2h(l + b)
where l = 10.2 m, b = 8.5 m, h = 4.6 m
So,
Total S.A = 2 × 4.6(10.2 + 8.5)
= 9.2(18.7)
= 9.2 × 18.7
= 172.04 m²
Area of Door = 1.5 × 2.6
= 3.9 m²
Area of window = 2 × 1.7
= 3.4 m²
Thus,
Area of wall = 172.04 - 3.9 - 3.4
= 164.74 m²
Now, The cost of tiling 1 m² = ₹ 13.50
∴ Cost of Tiling 164.74 m² = ₹ (164.74 × 13.50)
= ₹ 2,223.99
= ₹ 2,224 (approximately)
Hope it helped and you understood it........All the best