Question

6. A sample of hydrogen gas has 100 hydrogen
molecules. Each molecule is supplied with 10
eV of energy. The maximum number of emis-
sion spectral lines obtained is​

Answer 1

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Explanation:

detail of my friends are not going out of stock for you and the family of four of

Answer 2

Answer:

Zero

Explanation:

Given

A sample of hydrogen gas has 100 hydrogen molecules and each molecule is supplied with 10 eV of energy

Energy of an electron in the  Hydrogen atom = -13.6($Z^{2} /n^{2}$)ev

    Where  Z = atomic number = 1 for Hydrogen atom

                 n = shell number

Energy for first shell of an Hydrogen atom = -13.6($1^{2}/1^{2}$)ev

                                                                       = -13.6ev

energy supplied to each molecule = 10 ev

∴ total energy of the Hydrogen molecule = -13.6 +10

                                                                      = -3.6ev

Now

                     - 13.6($Z^{2} /n^{2}$)   =  -3.6

                      -13.6(($1^{2}/ n^{2}$)   =  -3.6

                      ⇒     n    ≈     1.9

i.e  1 < n < 2 . Since value of n is less than 2 , the electron cannot be excited to the 2nd shell. Therefore there will be no emission of  spectral lines. hence number of spectral lines obtained is zero.

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