6. A shell of mass 25 kg is fired horizontally with a velocity of 15 m/s. It explodes and breaks into two pieces of 15 kg. and 10 kg. If the former is brought to rest after the explosion, determine the velocity of the later. [Ans. 37.5 m/s]
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Explanation:
according to the law of conservation of momentum,
total momentum before explosion = total momentum after the explosion. _ _ _(1)
initially,
total momentum = mv
= 25 * 15
= 375 kgm/s
after explosion
total momentum = m(1)v(1) + m(2)v(2)
= 15 * 0 + 10*v(2)
= 10*v(2)
from eq(1)...
initial total momentum = final total momentum
→ 375 = 10*v(2)
→ v(2) = 375/10
→ v(2) = 37.5 m/s
hence, the velocity of the 10 kg shell is 37.5 m/s
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