Math, asked by SupremePriya, 8 months ago

6. A shopkeeper bought oranges at the rate of 7 for Rs 5 and sold them at profit of
40 percent. How many oranges would a customer get for a rupee?

Answers

Answered by sayalipatil0897
4

Answer:

Step-by-step explanation:The shopkeeper bought 7 oranges for a rupee and sold them at a profit of 40% How many oranges did he sell for a rupee?

Cost price of 7 oranges = Re.1. Hence the selling price of 7 oranges is Rs.1.40 (with a profit of 40%).

If Rs. 1.40 is the selling price of 7 oranges

then Re.1.00 is the selling price of 1.00*7/1.40 or 5 oranges.

He sold 5 oranges for Re.1.

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Answered by ramchandrabrahma7
0

Answer:

1 orange.

Step-by-step explanation:

step 1: without adding profit for Rs 1 customer will get 7/5 oranges,

step 2: with adding 40% profit i.e. for Rs 1.40 customer will get 7/5 oranges.

step 3: {now we have to find for Rs 1 from Rs 1.40, means (7/5)/1.40, same as step 1}

Therefore, for Rs 1 with 40% profit customer will get 1 orange.

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