Question

6.
A small indoor greenhouse (herbarium) is made entirely of glass panes (including
base) held together with tape. It is 30 cm long, 25 cm wide and 25 cm high.
(i) What is the area of the glass?
(ii) How much of tape is needed for all the 12 edges?​

Answer 1

Answer:

area is 18750

this is your answer

2 answer I don't

Answer 2

Question ::-

A small indoor greenhouse (herbarium) is made entirely of glass panes (including base) held together with tape. It is 30 cm long, 25 cm wide and 25 cm high.

(i) What is the area of the glass?

(ii) How much of tape is needed for all the 12 edges?

Given ::-

• length = 30cm

• Breadth = 25cm

• Height = 25cm

To find ::-

• What is the area of the glass?

• How much of tape is needed for all the 12 edges?

Solution ::-

The herbarium is like a cuboid.

Here,

• length (l) = 30 cm,
• breadth (b) = 25 cm,
• height (h) = 25 cm

_________

(i) Surface area of the herbarium (glass)

$➠ \: \: \: \: \: \: \: \: 2[lb + bh + hl]$

$➠ \: \: \: \: \: \: \: \: 2[(30 \times 25) + (25 \times 25) + (25 \times 30)] {cm}^{2} – 2[750 + 625 + 750] {cm}^{2}$

$➠ \: \: \: \: \: \: \: \: 2[2125] {cm}^{2}$

$➠ \: \: \: \: \: \: \: \: 4250 {cm}^{2}$

Thus, the required area of the glass = 4250 ${cm}^{2}$

_________

(ii) Total length of 12 edges = 4l + 4b + 4h

= 4(l + b + h)

= 4(30 + 25 + 25) cm

= 4 x 80 cm

= 320 cm

Thus, the required length of tape = 320 cm