Math, asked by Hrithikas, 2 days ago

6. A solid iron pole consists of a cylinder of height 220 cm and base diameter 24 cm, which
is surmounted by another cylinder of height 60 cm and radius 8 cm. Find the mass of the
pole, given that 1 cm of iron has approximately 8g mass. (Use A = 3.14)​

Answers

Answered by renusankar
1

Answer:

Height (h

1

) of larger cylinder =220 cm

Radius (r

1

) of larger cylinder =

2

24

=12 cm

Height (h

2

) of smaller cylinder = 60 cm

Radius (r

2

) of smaller cylinder =8 cm

Total volume of pole = Volume of larger cylinder + Volume of smaller cylinder

=πr

1

2

h

1

+πr

2

2

h

2

=(π(12)

2

×220)+(π(8)

2

×60)

=π[144×220+64×60]

=3.14[31,680+3,840]

=3.14×35520=111,532.8 cm

3

Mass of 1 cm

3

iron = 8 g

Mass of 111532.8 cm

3

iron = 11532.8×8=892262.4 g

Answered by nanakadam34
1

Answer:

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