Question

6. A solid iron pole consists of a cylinder of height 220 cm and base diameter 24 cm, is surmounted by another cylinder of height 60 cm and radius 8 cm. Find the mass of pole, given that I cm’of iron has approximately 8g mass. (Use t = 3.14) ​

Answer 1

SOLUTION:

We can see that,

Volume of the solid iron pole = volume of larger cylinder + volume of smaller cylinder

Mass of iron in the pole = 8 g × volume of the solid iron pole

We will find the volume of the solid by using formula;

Volume of the cylinder = πr2h where r and h are the radius and height of the cylinder respectively

Radius of larger cylinder, R =$\frac{24}{2} cm = 12cm$

Height of larger cylinder, H $= 220cm$

Radius of smaller cylinder, r $= 8cm$

Height of smaller cylinder, h $= 60cm$

Volume of the solid iron pole = volume of larger cylinder + volume of smaller cylinder

= πR2H+πr2h

= π(12 cm × 12 cm × 220 cm + 8 cm × 8 cm × 60 cm)

= 3.14 × (31680 cm3 + 3840 cm3)

= 3.14 × 35520 cm3

= 111532.8 cm3

Mass of 1 cm3 iron is 8 g

Mass of iron in the pole = 8 g × volume of the solid iron pole

= 8 g × 111532.8

= 892262.4 g

= 892262.4/1000 kg

= 892.2624 kg

Thus, the mass of iron in the pole is 892.26 kg.

THANK YOU

HAVE A NICE DAY

PLEASE MARK ME AS BRAINLIEST