Question

6. (a) Solve for 0 : 4 cos 9 - 3 = 0,0° < < 90°.​

Answer 1

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If root 3 sin theta-cos theta=0 and 0 < theta <90°, find the value of theta.

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√3sinθ - cosθ = 0

√3sinθ = cosθ

√3 = cosθ / sinθ

√3 = cotθ

but we know that, cot30° = √3

∴ cotθ = cot30°

θ = 30°

Answer 2

$\huge \pink {correct\:question}$

If root 3 sin theta-cos theta=0 and 0 < theta <90°, find the value of theta.

$\huge \pink {answer}$

⠀

√3sinθ - cosθ = 0

√3sinθ = cosθ

√3 = cosθ / sinθ

√3 = cotθ

but we know that, cot30° = √3

∴ cotθ = cot30°

θ = 30°