6. A square of side 3 cm is cut out from a circle of radius 2.12 cm. Find the area of the remaining part? 7. Meera has a basket as show in the adjacent figure. If the cost of painting its flat surfaces is 37/m? how much would Meera pay to have it painted on both sides? a 8. Rukmini tied a satin ribbon around a scroll making 3 rounds using 56 cm of the ribbon each time. She used another 12 cm to make a bow. Find the total cost of the ribbon if the cost per meter was 15. Find the radius of the scroll.
Answers
Answer:
6)r = 2.12 cm
Square of side = 3 cm
Area of square = 3²
= 9 sq cm
Circle area = πr²
= 22/7×(2.12)²
= 98.8768/7 sq cm
Remaining area = 9 — (98.8768/7)
= (63 — 98.8768)/7 sq cm
= 35.8768/7 sq cm
7)Area of one wall =length×height=5×8=40 sq.m
Area of another adjacent wall =width×height=3×8=24 sq.m
Area of 4 walls =2×40+24×2−4.5−2.25=128−6.75=121.25
Cost of painting the four walls =121.25×25=3,031.25 Rs.
So, we don't require statement III.
8)Given : Rukmini tied a satin ribbon around a scroll making 3 rounds using 56 cm of the ribbon each time
She used another 12 cm to make a bow.
cost per meter was 15.
To Find : total cost of the ribbon
Solution:
Total length of ribbon used = 56 x 3 + 12
= 168 + 12
= 180 cm
= 180/100 m
= 1.8 m
cost per meter was 15.
Total Cost = 15 x 1.8 = 27 Rs
56 cm = perimeter
=> 56 cm = 2π R
R = Radius of Scroll
=> 56 = 2(22/7) * R
=> R = 8.91 cm
radius of the scroll. = 8.91 cm
Hope this is helpful
Regards,
Ganaadheesh