Question

6. A sum of 1,900/- is divided among A, B
and C such that
A's share B's share 2
B's share C's share 3
Then A's share is
(1) 400
(3) 900
(2) 600
(4) 950​

Answer 1

Answer:

PLS MARK ME AS THE BRAINLIEST

A's share = 1140     B's share = 570      C's share = 190

Step-by-step explanation:

Total amount of money = 1900

Let A's share = x

B's share = y

C's share = z

According to the question

x = 2y

y = 3z

⇒ x = 2y = 6z

⇒ y = $\frac{x}{2}$

⇒ z = $\frac{x}{6}$

⇒ $x+\frac{x}{2}+\frac{x}{6} =1900$

⇒  $\frac{6x+3x+x}{6}$ $= 1900$

⇒ 10x= 1900×6

⇒ $x=\frac{11400}{10}$ $= 1140$

⇒ $y = \frac{x}{2} = \frac{1140}{2} = 570$

⇒ $z = \frac{x}{6} = \frac{1140}{6} = 190$

⇒ A's share = 1140     B's share = 570      C's share = 190