6. A train travels 45 1/3 km every hour for the first 3 1/2 hours after leaving a station. After that it
travels 50 1/2 km every hour for the next 2 1/2 hours. What distance does the train travel during
the six hours?
Answers
Answered by
0
Answer:
Answer:
Answer:44.5 km
Answer:44.5 kmduring first 3 1/2 hr distance travelled(s) = 45 1/3 × 3 1/2 = 37/2 km
Answer:44.5 kmduring first 3 1/2 hr distance travelled(s) = 45 1/3 × 3 1/2 = 37/2 kmduring next 2 1/2 hr distace (s')= 50 1/2 × 2 1/2 = 26 km
Answer:44.5 kmduring first 3 1/2 hr distance travelled(s) = 45 1/3 × 3 1/2 = 37/2 kmduring next 2 1/2 hr distace (s')= 50 1/2 × 2 1/2 = 26 kmtotal distance = s + s'= 44.5 km
Answered by
0
Answer:
44 1/2 = 44.5 ans.
Step-by-step explanation:
first travel = 45 1/2 × 3 1/2 = 37/2 km
second travels = 50 1/2 × 2 1/2 = 26 km
37/2 +26/1 = 89/2 = 44 1/2 = 44.5 ans.
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