Question

6 A Transformer has 1000 turns and 240V,0.2 A in the primary coil. If the current through secondary coil is 0.4 A 0. (b) Find the voltage and number of turns in the secondary coil?
(c) Calculate the maximum power in the secondary coil of this transformer. ​

Answer 1

Answer:

Let the number of turns in secondary coil be n.

no of turns in primary × current in primary = turns in secondary × current in secondary

1000 × 0.2 = n × 0.4

n = 500

No of turn in secondary is 500

Voltage in secondary coil

== 1000×V = 500×240

== V = 120

Maximum power in Secondary =

VI = 120× 0.4 = 48Watt