6. A Trolley of mass 50 Kg starts from rest and rolls down on an inclined road in a hilly region with
a constant acceleration. travels a distance of 200 m in 10 s. Calculate the Force acting on it.
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Explanation : m = 50 kg
Rest : u = 0 m/s
s = 200 m
t = 10 sec
F = ma
From 2nd eq of motion we will find acceleration.
s = ut +1/2at^2
s = 1/2at^2
200 = 1/2 ×a ×100
4 m/s^2 = a.
F = ma = 50 × 4 = 200 kg m/s^2.
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