Math, asked by Naveedullah, 1 year ago


6. A well is 50 m deep and its diameter is 4 m. How many tiles will be
the required to cover all its inner surface iſ the area of one tile is 0.9 m?


Anonymous: 0.9 m² or what
Naveedullah: yes .9m^2

Answers

Answered by zack2365
2

Answer:

627

Step-by-step explanation:

HEIGHT OF WELL = 50 M

RADIUS= DIAMETER/2= 4/2= 2M

INNER SURFACE AREA = 2*PI*R*H

PUTTING VALUES

LET US TAKE PI= 3.14

2*3.14*50*2

=628 M

AREA OF TILE =0.9 M

NO. OF TILES REQUIRED= AREA OF WELL/ AREA OF ONE TILE

628/0.9=627 TILES


Naveedullah: but in book answer is 727
zack2365: MULTIPLICATION ERROR SORRY
Answered by bsmaths130
0

Answer:

Total Area of well = 2πr ( h+r)

here r= 2, π =3.1416, h= 50

putting value in above equation, we get

Total Area = 653.45127

Tile required = Total Area / Area of one tile

Tile required = 653.45127/ 0.9 = 726.05

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