Question

6. A wire is in the shape of a circle of radius 21 cm. It is bent in the form of a square. The side of the square is { use π = 22/7 } (a) 22 cm (b) 44 cm (c) 66 cm (d) 33 cm



Spams not allowed ​

Answer 1

Answer:

length of wire =circumference of

circle

=2Rr

=2×22/7×42=46c cm

length of wire =perimeter of square

264= 4a

so a =264/4=66cm

side of equation =66cm

Step-by-step explanation:

tq

Answer 2

Answer:

d) 33 cm

Step-by-step explanation:

Given that a wire is in the shape of a circle of radius 21 cm. It is bent in the form of a square. We need to find out the side of the square.

Let's say that the side of the square is x.

Since, a wire which is in the shape of circle is bent to form a square then it's perimeter (perimeter of circle) will be equal to perimeter of square.

Perimeter of circle = Perimeter of square

2πr = Perimeter of square

Given value of radius is 21 cm and π is 22/7. Substitute the values,

2 × 22/7 × 21 = Perimeter of square

44 × 3 = Perimeter of square

132 = Perimeter of square

And we know that, perimeter of square is square of side.

So,

Perimeter of square = 4(side)

132 = 4(side)

side = 132/4

side = 33

Therefore, the side of the square is 33 cm.