Question

6. A wire is in the shape of a rectangle. Its length is 40 cm and breadth is 22 cm. If the
same wire is rebent in the shape of a square, what will be the measure of each side.
Also find which shape encloses more area?

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Answer 1

Answer:

Step-by-step explanation:

According to the question,

Perimeter of square=Perimeter of rectangle

⇒4× side=2(length+breadth)

⇒4×side=2(40+22)

⇒4×side=2×62

⇒ side=  

4

2×62

​  

=31cm

Thus, the side of the square is 31cm.

Now, Area of rectangle=length×breadth=40×22=880cm  

2

 

And Area of square=side×side=31×31=961cm  

2

 

Therefore, on comparing, the area of square is greater than that of rectangle.

Answer 2

Given:

Length of the rectangle = 40 cm

Breadth of the square = 22 cm

Then we will get:

Perimeter of the rectangle = Perimeter of the Square

2 (Length + Breadth) = 4 × side

2 (40 + 22) = 4 × side

2 (62) = 4 × side

124 = 4 × side

Side = 124/4

Side = 31 cm

So, Area of the rectangle = (Length × Breadth)

= 40 × 22

= 880 cm²

Area of square = side²

= 312

= 31 × 31

= 961 cm²

∴Square shaped wire encloses more area.