Question

6. (a) यदि fix) = x + kx-4x + 12 को एउटा गुणनखण्ड x + 2 भए
k को मान पत्ता लगाउनुहोस् ।
If (x + 2) is a factor of f(x) = x + kx² - 4x + 12 then find
the value of k.
Ans:-3​

Answer 1

Answer:

here,

f(x)=x+kx-4x+12

d(x)=x+2

let comparing x+2 with x-c=0

x=-2

now, putting the value of x in f(x)

f(x)=2-2k-4×(-2)+12

=2-2k-8+12

=-2k+6

=-2k=-6

=k=-6/-2

k=3