Question

6 (a³b²c² + a²b³c² + a²b²c³) ÷ 2a²b²c²




divede the give polynomial by given monnomial​

Answer 1

Step-by-step explanation:

Taking a^2×b^2×c^2 as common

6×a^2×b^2×c^2(a+b+c)÷2a^2×b^2×c^2= 3(a+b+c)